Question

Very confused on this, could someone please help? I’m currently in pre calculus if that helps!

Answer 1

• tan x<0 lies in second quadrant

sec x =3/4

• cosX=1/secx=4/3

$\\ \tt\Rrightarrow sin x=\sqrt{1-(4/3)^2}=\sqrt{1-16/9}=\sqrt{-7/9}$=√7/3i[/tex]

Now

• tanx=(√7/3i)(4/3)=√7/4i