Question

HELP ASAP !!
A +2.0 C and a +2.0 C charge exert 0.10 N of force on each other. How much would a +2.0 C and a +4.0 C charge exert, if they were the same distance apart?

Answer 1

This question involves the concept of Colomb's Law and electrostatic force.

The electrostatic force will be "0.2 N".

COLOMB'S LAW:

According to Colomb's Law, every charge exerts an electrostatic force on the other charge, which is directly proportional to the product of the magnitudes of both the charges and inversely proportional to the square of the distance between them.

$F=\frac{kq_1q_2}{r^2}$

where,

• F = electrostatic force
• k = Colomb's constant = 9 x 10⁹ N.m²/C²
• q₁ = magnitude of first charge
• q₂ = magnitude of second charge
• r = distance between charges

In case of +2 C charges:

• q₁ = q₂ = 2 C
• r = ?
• F = 0.1 N

Therefore,

$0.1\ N = \frac{(9\ x\ 10^9\ N.m^2/C^2)(2\ C)(2\ C)}{r^2}\\\\r^2=\frac{(9\ x\ 10^9\ N.m^2/C^2)(2\ C)(2\ C)}{0.1\ N}\\\\r^2=3.6\ x\ 10^{11}\ m^2$

Now, for the second case:

• F = ?
• q₁ = 2 C
• q₂ = 4 C
• r² = 3.6 x 10¹¹ m²

Therefore,

$F=\frac{(9\ x\ 10^9\ N.m^2/C^2)(2\ C)(4\ C)}{3.6\ x\ 10^{11}\ m^2}$

F = 0.2 N

Learn more about Colomb's Law here:

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