Question

Which statement is true concerning the vertex and axis of symmetry of h(x)=−2x2+8x?

The vertex is at (0, 0) and the axis of symmetry is x = 2.
The vertex is at (0, 0) and the axis of symmetry is y= 2.
The vertex is at (2, 8) and the axis of symmetry is x = 2.
The vertex is at (2, 2) and the axis of symmetry is y = 2.

Answer 1

Answer:

The vertex is at (2, 8) and the axis of symmetry is x = 2

Step-by-step explanation:

First, let's find the zeros of the equation

Factor the equation

-2x² + 8x = -2x(x - 4) = 0

-2x = 0

x - 4 = 0

h(x) is 0 when x = 0 or 4

Now we add those zero's together and divide by 2 to find the middle (the axis of symmetry)

4 + 0 = 4

4 ÷ 2 = 2

Now plug 2 into the original equation to find the vertex

h(x) = -2(2)² + 8(2) = 8

Since h(x) equals 8 at the axis of symmetry, which is 2, our vertex is (2,8)

Answer 2

Answer:

The vertex is at (2, 8) and the axis of symmetry is x = 2

Step-by-step explanation:

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