Question

Calculate the molality of a sucrose solution made by dissolving 37.4 grams sucrose into 94.2 grams water. The molar mass of sucrose is 342.2 g/mol. Record your answer in scientific notation using 3 significant figures

Answer 1

The molality of the sucrose solution is 1.16 m

Definition of molality

The molality of a solution is defined as the mole of solute per unit kilogram (Kg) of water. Mathematically, it can be expressed as:

Molality = mole / mass (Kg) of water

How to determine the mole of sucrose

• Mass of sucrose = 37.4 g
• Molar mass of sucrose = 342.2 g/mol

• Mole of sucrose =?

Mole = mass / molar mass

Mole of sucrose = 37.4 / 342.2

Mole of sucrose = 0.109 mole

How to determine the molality

• Mole of sucrose = 0.109 mole
• Mass of water = 94.2 g = 94.2 / 1000 = 0.0942 Kg
• Molality =?

Molality = mole / mass (Kg) of water

Molality of sucrose = 0.109 / 0.0942

Molality of sucrose = 1.16 m

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