Question

Find the vertex of y=1/2x^2+2

Answer 1

Answer:

$(0,2)$

Step-by-step explanation:

Determine x-coordinate of vertex

$x=-\frac{b}{2a}\\ \\x=-\frac{0}{\frac{1}{2}}\\\\x=0$

Determine y-coordinate of vertex

$y=\frac{1}{2}(0)^2+2$

$y=2$

Therefore, the vertex is at $(0,2)$