Question

How many grams of calcium carbonate were used if you drew the periodic table on the sidewalk using
1.505x1023 atoms of calcium carbonate? hint: This is a two-step calculation.
(Show your complete calculation below)
HELP PLS!!!!!

Answer 1

Based on the data provided, there are 25 g of calcium carbonate in 1.505 × 10^23 atoms.

What is the moles of calcium carbonate in 1.505 × 10^23 atoms of calcium carbonate?

The mole of a substance can be calculated as follows:

• Moles of substance = number of particles/6.02 × 10^23

Moles of calcium carbonate = 1.505 × 10^23/6.02 × 10^23

Moles of calcium carbonate = 0.25 moles

The mass of calcium carbonate in 0.25 moles is calculated as follows:

• mass = moles × molar mass

molar mass of a calcium carbonate = 100 g/mol

mass of calcium carbonate = 0.25 × 100 = 25 g.

Therefore, there are 25 g of calcium carbonate in 1.505 × 10^23 atoms.

Learn more about molar mass and mass at: https://brainly.com/question/15476873