Question

There are five candies in a bag. Three are chewy, and two are chocolate. You draw a candy, do not replace it, and then draw another. What is the probability of choosing two chocolate candies?

Answer 1

P(Chocolate) for first draw = 2/5

P(Chocolate) for second draw = 1/4

Prob. of choosing two chocolate candies = 2/5 * 1/4 = 1/10

Answer 2

Probability of choosing two chocolates candies without replacement is equals to (1/ 10).

What is probability?

" Probability is defined as the mathematical expression which represents the ratio of number of favourable outcomes to the total number of outcomes for a given event."

Formula used

Probability = $\frac{Number of favourable outcomes}{Total number of outcomes}$

According to the question,

Total number of candies = 5

Number of chocolates = 2

As per the condition of without replacement we have,

Probability of  drawing a first chocolate = 2 / 5                              ___( 1 )

Probability of  second chocolate without replacing first one =  1/ 4  __( 2)

From ( 1 )  and (2) we get,

Probability of choosing 2 chocolates candies without replacement

= $\frac{2}{5}$ × $\frac{1}{4}$

= (1 / 10)

Hence, probability of choosing two chocolates candies without replacement is equals to (1/ 10).

Learn more about probability here

https://brainly.com/question/11234923

#SPJ2