Respuesta :

Explanation:

Molar mass of

B

=

10.81

g

m

o

l

1

. If there are 36 odd grams of

B

, there are approx.

7

2

×

N

A

boron atoms, where

N

A

is Avogadro's number.

Explanation:

35.76

g

10.81

g

m

o

l

1

×

6.022

×

10

23

m

o

l

1

=

?

?

Answer link

MAT

Nov 15, 2015

1.991

×

10

24

Explanation:

Molar mass of B = 10.81g/mol

So, 1 mole of B = 10.81g

and 1 mole =

N

A

=

6.023

×

10

23

By combining,

10.81g of B =

6.023

×

10

23

atoms of B

thus,

35.76g of B =

6.023

×

10

23

10.81

×

35.76

35.76g of B =

1.991

×

10

24

48.176 × 10¹⁷ atoms of boron are present in 8.0 × 10⁻⁶ moles of boron.

Avogadro's Number

Avogadro's number is the number of particles in one mole of substance. 6.022 × 10²³ is known as Avogadro's constant / Avogadro's number.

Avogadro's number = 6.022 × 10²³

How to find the number of atoms ?

Number of atoms = Number of moles  × Avogadro's Number

                             = 8.0 × 10⁻⁶ × 6.022 × 10²³

                             = 48.176 × 10¹⁷ atoms of boron

Thus, from the above conclusion we can say that 48.176 × 10¹⁷ atoms of boron are present in 8.0 × 10⁻⁶ moles of boron.

Learn more about the Avogadro's Number here: brainly.com/question/859564

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