side of the square = 4cm
We will use pythagoras theorum
(Hy)² = (Base)² + (Height)²
(Hy)² = (4)² + (4)²
(Hy)² = 16 + 16
(Hy)² = 32
(Hy)² = (6)²
Powers are same so they will be cancelled
Hy = 6cm
ANSWER :-
The length of the diaginal is 6cm
