Question

Please show work answer fast In the figure, ABCD is a square and EFGC is a trapezoid. CE = BE, ∠EFG = 110° and ∠230°

Find ∠FGC

Find ∠CBE

Answer 1

Answer:

FGC: 70 degrees.

CBE: 50 degrees.

Step-by-step explanation: EFGC is a trapezium.

EF//GC

<EFG+FGC=180 degrees

< EFG=110 degrees

<FGC= 180-110 degrees = 70 degrees

<DCG=230 degrees <DCB= 90 degrees

<BCG= 36-230-90=40 degrees

EF//GC <FEC=90 degrees

ECA=90 degrees

ECB=90-40=50 degrees

CE=BE (Isosceles triangle) <CBE= ECB=50 degrees