Question

Find the equation of the line in slope-intercept form that passes through the points (-2,-4) and (-3,2).

Answer 1

Answer:

$y=-6x-16$

Step-by-step explanation:

Slope intercept formula: $y=mx+b$

Slope

Using two points formula:               $\boxed{\frac{y_2-y_1}{x_2-x_1}}$

Plug the points in and solve:          $\frac{2-(-4)}{-3-(-2)}$

                                                         $=\frac{6}{-1}$

                                                         $=-6$

m = -6

y-intercept

Plugin one point into the slope-intercept formula with the slope, and solve: (-2, -4)

$-4=-2(-6)+b$

Simplify                                          $-4=12+b$                                      

Subtract 12 from both sides:        $-4-12=12+b-12$                      

                                                      $=16$

b = -16

Therefore, the equation is $\bold{y=-6x-16}$