Question

An object accelerates from rest (v0), with a constant acceleration of 8.6 m/s^2 (a), what will its velocity (v) be after 7.2 s (t)?

Answer 1

Answer: 61.92 m/s We will use the equation vf = vo + at. Vo is zero, t is 7.2 and a is 8.6 So vf = 7.2 * 8.6 =61.92

Answer 2

Answer:

Hey,

QUESTION)

Simple formula application :

$a = \frac{v}{\Delta t} \Longleftrightarrow v = a \times \Delta t\\ v = 8,6 \times 7,2 \\ v \approx 62 \text{ m/s}$