Question

Which shows the four-term polynomial and factored form of x2 6x – 27? x2 3x – 9x – 27 = (x 3)(x – 9) x2 6x – 3x– 27 = (x 6)(x – 3) x2 9x – 3x – 27 = (x 9)(x – 3) x2 3x – 6x – 27 = (x 3)(x – 6).

Answer 1

None of the polynomials has four terms in it.

Polynomial

It is the sum of terms in which the variable is in decreasing power of n.

Given

Polynomial is in factor form

$\rm 1.\ (x^{2} )(6x-27)(x^{2} )(3x)(-9x -27)\\ 2.\ (x^{3} )(x-9)(x^{2} )(6x)(-3x-27)\\ 3.\ (x^{6} )(x-3)(x^{2} )(9x)(-3x-27)\\ 4.\ (x^{9} )(x-3)(x^{2} )(3x)(-6x-27)\\ 5.\ (x^{3} )(x-6)$

How to solve polynomial?

$\begin{aligned} \rm 1.\ &(x^{2} )(6x-27)(x^{2} )(3x)(-9x -27)\\ &-162x^{7}- 243x^{6} +2187x^{5} \\ 2.\ &(x^{3} )(x-9)(x^{2} )(6x)(-3x-27)\\ &-18x^{8} +1458x^{6} \\ 3.\ &(x^{6} )(x-3)(x^{2} )(9x)(-3x-27)\\ &-27x^{11}-162 x^{10} 729x^{9} \\ 4.\ &(x^{9} )(x-3)(x^{2} )(3x)(-6x-27)\\ -&18x^{13} -27x^{12} +243x^{11} \\ 5.\ &(x^{3} )(x-6)\\ &x^{4} -6x^{3} \\ \end{aligned}$

Thus, none of the polynomials has four terms in it.

More about the polynomial link is given below.

https://brainly.com/question/17822016