If Boston Red Sox baseball legend, Carl Yaztremski, hit a baseball due west with a speed of 50.0m/s, and the ball encountered a wind that blew it north at 5.00 m/s, what was the resultant velocity of the baseball?

Respuesta :

Chybie

Answer: 50.2 m/s towars northeast, also travels at 5.71 degrees.

Explanation:

(50.0 m/s)^2 +(5.0 m/s)^2 =c^2

c= [tex]\sqrt[n]{2500 m^2/s^2 +25.0 m^2/s^2}[/tex]

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