I need help with this Algebra problem please!!!!!!
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Answer: D
Step-by-step explanation:
Switch the x and y values:
[tex]f(x)=2^x+6[/tex]
[tex]y=2^x+6[/tex]
[tex]x=2^y+6[/tex]
Now we have to solve for the y value. Subtract 6 on both sides:
[tex]x-6=2^y[/tex]
If we take the log of both sides, with a base of 2, the right hand side will be explicitly solved for y:
[tex]log_2(x-6)=log_2(2^y)=y[/tex]