Question

Suppose that the acceleration due to gravity is about 10 meters per second, every second, and that you threw the rock upward with an initial speed of 40 meters per second. Six seconds after the rock left your hand, the speed of the rock would be

Answer 1

Answer:

Explanation:

Use the kinematic formula:

$V_f=V_i+at$

$V_f=(40m/s)+(10m/s^2)(6s)$

$V_f=40m/s+60m/s$

$V_f=100m/s$