Respuesta :

The solution of the equation is (3, 1/2).

We have to determine

What is the solution to this system of equations?

According to the question

The given system of the equation;

[tex]\rm x+2y=4\\ \\ 2x-2y=5[/tex]

The standard form for linear equations in two variables is;

[tex]\rm Ax+By = C[/tex]

On comparing equation 1 and equation 2 with the standard form we get,

[tex]\rm a_1 = 1,\ b_1 = 2,\ c_1=4\\ \\ a_2=2, \ b_2=-2, \ c_1 = 5[/tex]

Here,

[tex]\rm \dfrac{a_1}{a_2} = \dfrac{1}{2}\\ \\ \dfrac{b_1}{b_2} = \dfrac{-2}{2} = -1\\ \\ \dfrac{a_1}{a_2} \neq \dfrac{b_1}{b_2}[/tex]

Here,  [tex]\rm \dfrac{a_1}{a_2} \neq \dfrac{b_1}{b_2}[/tex] so, the given system of equations has a unique solution.

Then,

The solution of the equation is;

[tex]\rm x+2y=4\\\\2x-2y=5[/tex]

On adding both the equation;

[tex]\rm x+2y+2x-2y=4+5\\ \\ 3x=9\\ \\ x = \dfrac{9}{3}\\ \\ x = 3[/tex]

Substitute the value of x in equation 1,

[tex]\rm x+2y=4\\ \\ 3+2y = 4\\ \\ 2y = 4-3\\ \\ 2y=1\\ \\ y =\dfrac{1}{2}[/tex]

Hence, the solution of the equation is (3, 1/2).

To know more about System of Equation click the link given below.

https://brainly.com/question/1568892

Answer:

(3,1/2)

Step-by-step explanation:

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