Four students were loading boxes of food collected during a food drive. The force that each student exerted while lifting and the distance each box was lifted are listed in the table. A 3-column table with 4 rows. The first column labeled student has entries Chet, Mika, Sara, Bill. The second column labeled Force (Newtons) has entries 50, 40, 30, 60. The third column labeled Distance (meters) has entries 1. 0, 2. 0, 1. 5, 0. 5. Which lists the students in order from the greatest amount of work done to the least? (Work: W = Fd) Bill, Sara, Chet, Mika Mika, Chet, Sara, Bill Bill, Chet, Mika, Sara Mika, Sara, Chet, Bill.

When some force is applied to an object to displace it for some specific distance, then the product of applied force and distance moved is known as work done.

Given data:

Distance covered by Chet, Mika, Sara, and Bill are, 1.0 m, 2.0 m, 1.5 m, and 0.5 m.

The magnitude of an applied force by Chet, Mika, Sara, and Bill are 50 N, 40 N, 30 N, and 60 N.

The expression for the work done by each of Chet, Mika, Sara and Bill are,

W = F × d

here, F is the magnitude of applied force and d is the distance covered.

Then, For Chet

W1 = 50 × 1.0

W1 = 50 J

For Mika,

W2 = 40 × 2.0

W2 = 80 J

For Sara,

W3 = 30 × 1.5

W3 = 45 J

For Bill,

W4 = 60 × 0.5

W4 = 30 J.

Clearly, the order of work done is Mika > Chet > Sara > Bill

Thus, we can conclude that the order of work done from the greatest to the least is, Mika, Chet, Sara, and Bill.

Learn more about the work done here:

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