Question

Help please :)
Mark and Amy live 435 miles apart. They are planning to meet somewhere between the two locations. If Mark travels at 60 mph and Amy travels at 45 mph, and Amy is planning on leaving two hours later than Mark, how many miles will Mark travel before they meet?

Answer 1

Answer:

Mark will travel 300 miles before they meet.

Step-by-step explanation:

Mark leaves 2 hours before Amy, so he will have traveled 120 miles by the time she left. Take 120 from 435: 315 miles to go. Each hour from this point, 105 miles will be closed, because Amy will have started traveling at 45 miles per hour. ( 60 + 45 = 105 ) You can take 105 from 315 3 times evenly ( representing 3 hours ). During those 3 hours, Amy has travelled 135 miles. 2 hours plus 3 hours is 5 hours. Mark has been traveling for 5 hours, and 60 times 5 is 300. 300 miles plus 135 miles equals 435 miles. Let me know if I need to break it down any better :)

Answer 2

Mark travelled a distance of 300 miles before he meet Amy.

What is the distance?

Distance is how far one thing is from another thing. It is also a measure of the space between two things. It can be measured along any path. The distance traveled can be measured with speed and time.

For the given question,

The formula to find distance, d=speed(s) × time(t)

Distance between Mark and Amy = 435 miles

Mark's speed = 60 mph

Amy's speed = 45 mph

Amy leaves two hours late than Mark.

If Mark starts at t then Amy starts at (t-2)

Mark's distance = 60t

Amy's distance = 45(t-2)

For the given situation, the equation is

$st = d$

⇒ $60t + 45(t-2)=435$

⇒ $60t+45t-90=435$

⇒ $105t=435+90$

⇒ $105t=525$

⇒ $t=\frac{525}{105}$

Thus distance traveled by Mark's is 60t

⇒ $(60)(5)$

⇒ $300 miles$

Hence we can conclude that Mark traveled a distance of 300 miles before he meet Amy.

Learn more about distance, speed and time here

https://brainly.com/question/21901071

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