The coordinates of point B' are (-3, 6).
Triangle ABC has vertices A(4, 5), B(0, 5), and C(3, –1).
The triangle is translated as 3 units to the left and 1 unit up.
What are the coordinates of B' after the translation?
Triangle ABC has vertices A(4, 5), B(0, 5), and C(3, –1).
The triangle is translated as 3 units to the left and 1 unit up.
To find the coordinates of B', we will shift the x-coordinate of point B to left by 3 units and the y-coordinate of point B to 1 unit up.
After the given transformation the coordinates of point B' would be:
[tex]\rm B(0, \ 5) = B (0-3, \ 5+1) = B(-3, \ 6)[/tex]
Therefore, the coordinates of point B' are (-3, 6).
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