1 please help guysss

Answer:
The value of x is 4√11.
Step-by-step explanation:
Here, we have given that the two sides of triangle are 24 and 20.
Finding the third side of triangle by pythagorean theorem formula :
[tex]{\longrightarrow{\pmb{\sf{{(c)}^{2} = {(a)}^{2} + {(b)}^{2}}}}}[/tex]
Substituting all the given values in the formula to find the third side of triangle :
[tex]\begin{gathered}\qquad{\longrightarrow{\sf{{(c)}^{2} = {(a)}^{2} + {(b)}^{2}}}}\\\\\qquad{\longrightarrow{\sf{{(24)}^{2} = {(20)}^{2} + {(b)}^{2}}}}\\\\\qquad{\longrightarrow{\sf{{(24\times 24)} = {(20 \times 20)} + {(b)}^{2}}}}\\\\\qquad{\longrightarrow{\sf{{(576)} = {(400)} + {(b)}^{2}}}}\\\\ \qquad{\longrightarrow{\sf{{(b)}^{2} = 576 - 400}}}\\\\ \qquad{\longrightarrow{\sf{{(b)}^{2} = 176}}}\\\\\qquad{\longrightarrow{\sf{b = \sqrt{176}}}}\\\\\qquad{\longrightarrow{\sf{b = 4\sqrt{11}}}}\\\\\qquad\star{\underline{\boxed{\sf{\red{b = 4\sqrt{11}}}}}}\end{gathered}[/tex]
Hence, the value of x is 4√11.
[tex]\rule{300}{2.5}[/tex]