9th grade alg 1
number 43 and work please!

Answer:
Look below
Step-by-step explanation:
The equation is y=mx+b where m is the slope and b is the y-intercept.
We can find this by first calculating the slope by using any two x and y values
[tex]Slope = \frac{rise}{run} = \frac{y_{2}-y_{1}}{x_{2}-x_{1} } = \frac{-12+2}{3-1} =\frac{-10}{2} =-5[/tex]
Now we can plug the slope back into the equation to solve for the y-intercept
y=-5x+b
-12=-5(3)+b
-12=-15+b
b=3
Therefore the equation is y=-5x+3
Now we plug in the values for x/y to complete the table
y=-5(0)+3=0+3=3
y=-5(2)+3=-10+3=-7
68=-5x+3
65=-5x
x=-13
y=-5(25)+3=-125+3=-122
So the missing values (in order from left to right) are:
3, -7, -13, and -122