Respuesta :

Step-by-step explanation:

In traingle ABC

[tex]\\ \sf\longmapsto 40+90+<B=180[/tex]

[tex]\\ \sf\longmapsto <B+130=180[/tex]

[tex]\\ \sf\longmapsto <B=50°[/tex]

Now

[tex]\\ \sf\longmapsto x+100+50=180[/tex]

[tex]\\ \sf\longmapsto x=30°[/tex]

Answer:

Step-by-step explanation:

In ΔABC ,

∠A + ∠ACB + ∠B = 180 {Angle sum property of triangle}

40 + 90 + ∠B = 180

     130  + ∠B = 180

               ∠B = 180 - 130

              ∠B = 50

In ΔBFD ,

∠D + ∠B + ∠BFD = 180

x + 50 + 100 = 180

       x + 150 = 180

                x = 180 - 150

x = 30°

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