In the given figure, O is centre of the circle. Find the value of x and y?
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Answer:
x=30 cm
y=24 cm
Step-by-step explanation:
y=24 cm
x=√(24²+18²)=√[6²(4²+3²)]=6√(16+9)=6√25=6×5=30 cm
Answer:
Step-by-step explanation:
P is the exterior point to the circle with centre O
Radius = 5cm
Length of the tangent = 12 cm
Distance between the point and centre of the circle = x cm
We know that
The angle between the radius of the circle and the tangent at the point of contact is 90°
By Pythagoras Theorem
Hypotenuse² = Side²+Side²
⇛OP² = OT1² +PT1²
⇛x² = 24²+18²
⇛x² = 576+324
⇛x² = 900
⇛x² = 30²
⇛x = √(30)²
⇛x = √(30*30)
We know that
The lengths of tangents drawn from the exterior point to the circle are equal.
PT1 = PT2
Answer: Hence, the value of x=30cm and y = 18cm.
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