Question

hi can someone pls answer my question. i srsly need it

*with complete solution pls :(​

Answer 1

• Focal length=f=10cm
• Object distance=u=-5cm
• Height of object=h=1.67cm
• Height of image=h'=?
• Image distance=v=?
• Magnification=m=?

Apply mirror formula

$\\ \tt\longmapsto \dfrac{1}{v}+\dfrac{1}{u}=\dfrac{1}{f}$

$\\ \tt\longmapsto \dfrac{1}{v}=\dfrac{1}{f}-\dfrac{1}{u}$

$\\ \tt\longmapsto \dfrac{1}{v}=\dfrac{1}{10}-\dfrac{1}{-5}$

$\\ \tt\longmapsto \dfrac{1}{v}=\dfrac{1}{10}+\dfrac{1}{5}$

$\\ \tt\longmapsto \dfrac{1}{v}=\dfrac{1+2}{10}$

$\\ \tt\longmapsto \dfrac{1}{v}=\dfrac{3}{10}$

$\\ \tt\longmapsto v=\dfrac{10}{3}$

$\\ \bf\longmapsto v=3.3cm$

Now

$\\ \tt\longmapsto m=\dfrac{-v}{u}=\dfrac{-3.3}{-5}=\dfrac{3.3}{5}=0.6$

Now

$\\ \tt\longmapsto m=\dfrac{h'}{h}$

$\\ \tt\longmapsto h'=mh$

$\\ \tt\longmapsto h'=0.6(3.3)$

$\\ \tt\longmapsto h'=1.98cm$