Question

f:f(x²+3)² is defined on the set R of real numbers. Find the gradient of f(x) at x = 2
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Answer 1

Answer:

The gradient of the function at x = 2 is 56

Step-by-step explanation:

f : f(x² + 3)²

df / dx = 4x(x² +3)

At x = 2

df / dx (= gradient) = 4 x 2 x (2² + 3)

= 8 x (7)

= 56