A sample of helium is initially at 535 torr in a volume of 2.85 L.
If this sample of helium is at 24.7 °C, then What quantity in moles of
helium are present?

Respuesta :

Answer:

There are 0.082 moles of He present.

Explanation:

You would use the equation PV=nRT for this problem.

P (must convert to atm) = 535 torr/ 0.704 atm

V = 2.85 L

n = being solved for

R= 0.082 (universal gas constant for atm)

T (must convert to Kelvin)  = 24.7 celsius/ 297.85 K

This equals:

0.704(2.85)= n (0.082)(297.85)

2.0064 =24.42n

n= 0.082 moles

ACCESS MORE