Question

A skydiver drops himself from a plane, he passes 100 m before opening a parachute. if he experiences free fall motion, how much is his final speed at that point?

Answer 1

The final speed of the skydiver at the point is 44.3 m/s

Determination of the time

We'll begin by calculating the time required to fall 100 m

• Height (h) = 100 m

• Acceleration due to gravity (g) = 9.8 m/s²

• Time (t) =?

H = ½gt²

100 = ½ × 9.8 × t²

100 = 4.9 × t²

Divide both side by 4.9

t² = 100 / 4.9

Take the square root of both side

t = √(100 / 4.9)

t = 4.52 s

Determination of the velocity

Finally, we shall determine the velocity.

• Time (t) = 4.52 s

• Acceleration due to gravity (g) = 9.8 m/s²

• Velocity (v) =?

v = gt

v = 9.8 × 4.52

v = 44.3 m/s

Learn more about motion under gravity:

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Answer 2

Answer:

      I did this in school v^2 = u^2 + 2gh

v = final velocity

u = initial velocity

g = acceleration due to gravity

h = height

Since he dropped from a height, u = 0 m/s

v^2 = 0^2 + 2 (10) (100)

v^2 = 2000

v = √2000

v = 44.7 m/s

Explanation: