Answer:
a) 580 - 16n
b) 9850 - 271.72n
Step-by-step explanation:
a) starting number of bales = 580
each day, the farmer feeds out 2 bales of hay to each yard. he has 8 yards, so he feeds out 2 bales 8 times for a total of 2 * 8 = 16 bales. Therefore, he loses 16 bales each day
After the first day, he has 580-16 = 564 bales. After the second, he has 564-16 = 548 bales, and so on. He loses 16 bales n times for n days, and as a result, his final amount of bales is
original amount - amount lost = 580 - 16n
b)
First, we can calculate how much a bale weighs.
average = sum/count = 9850 kg / 580 ≈ 17 kg
Therefore, as he loses 16 bales of hay, he loses 17 kg 16 times, or approximately 271.72 kg of hay every day. For n days, he loses 271.72n kg. This brings his final amount to be
starting - amount lost = 9850 - 271.72n
a) Arithmetic sequence for the number of bales of hay remaining after n days :580 - 16n
b) Arithmetic sequence which approximates the mass of hay remaining after n days : 9850 - 271.72n
A sequence is an enumerated collection of objects in which repetitions are allowed and order matters.
A) number of bales = 580
As each day, the farmer feeds out 2 bales of hay to each yard.
So, he has 8 yards, so he feeds out 2 bales
Thus, he loses 16 bales each day
After the first day,
580-16 = 564 bales.
After the second,
564-16 = 548 bales, and so on.
He loses 16 bales for n days, and his final amount of bales = 580 - 16n
b) Average = 9850 kg / 580 = 17 kg
So, final amount to be
starting - amount lost = 9850 - 271.72n
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