Question

A shopping cart is pushed and released,
and eventually it slows to a stop. If the velocity of the 28-kg cart
after release is 3.5 m/s and it travels a distance of 6 meters before
stopping, determine the magnitude of the friction on the cart.

Answer 1

The magnitude of the friction on the cart is 28,56 N

To measure the deceleration of a car, without the value of the time of the movement, the Torricelli equation is used, which consists of:

                                  ${\displaystyle {v_{f}}^{2}={v_{o}}^{2}+2a\Delta s}$

Where is final velocity, is initial velocity, is acceleration, and is displacement.

Now, substitute the values ​​in the formula:

                                   $0^{2} = (3.5)^{2} + 2a6$

                                    $0 = 12.25 + 12a$

                                          $a = -\frac{12.25}{12}$

                                           $a = -1.02$

Finally, the value of the acceleration found is multiplied by the mass of the object, thus measuring the friction force:

                                        $F = 28\times-1.02$

                                         $F = -28.56 N$

Learn more about friction force at: brainly.com/question/13707283