Question

and a point on the line are known, the equation of the line can be found using the slope-intercept form, y=
Jalues of x and y using the coordinates of the given point, then determine the value of b.
mnique, find the equation of the line containing the points (-3,14) and (6,-1).
..

Answer 1

Answer:

Step-by-step explanation:

(-3,14)  ; (6 , -1)

x₁ = -3   ; y₁ = 14

x₂ = 6   ;  y₂ = -1

$Slope = \dfrac{y_{2}-y_{1}}{x_{2}-x_{1}}\\\\\\=\dfrac{-1-14}{6-[-3]}\\\\\\=\dfrac{-15}{6+3}\\\\=\dfrac{-15}{9}\\\\\\m=\dfrac{-5}{3}$

Slope intercept form: y = mx +b

y = (-5/3)x + b

Plugin x = -3 and y = 14

$14 = \dfrac{-5}{3}*(-3)+b\\\\14=5+b\\\\\\14 -5 = b\\\\b = 9$

Slope intercept form:

$y=\dfrac{-5}{3}x +9$