Respuesta :
(x^2-1)/(3x^2+5x+2)÷(x^2+6x-7)/(x^2-4x-5)
(x-1)(x+1)/3x^2+3x+2x+2 × x^2-4x-5/x^2+6x-7
(x-1)(x+1)/3x(x+1)+2(x+1) × x^2-4x-5/x^2+7x-x-7
(x-1)(x+1)/(3x+2)(x+1) × x^2-4x-5/x(x+7)-(x+7)
Divide numerator and denominator by x+1
x-1/3x+2 × x^2-4x-5/(x+7)(x-1)
Simplify the expression by dividing by x-1
1/3x+2 × x^2-4x-5/(x+7)
Multiply the fractions
x^2-4x-5/(x+7) (3x+2)
Multiply brackets
x^2-4x-5/3x^2+21x+2x+14
Calculate the sum
x^2-4x-5/3x^2+23x+14