Question

Suppose a miniature golf player sinks a hole-in-one about 12% of the time on any given hole and is going to play 8 games at 18 holes each.

What is the probability the golfer got zero or one hole-in-one during a single game?
What is the probability the golfer got exactly two holes-in-one during a single game?
What is the probability the golfer got six holes-in-one during a single game?

Answer 1

A) The probability the golfer got zero or one hole-in-one during a single game is between 10.01% and 11.38%.

B) The probability the golfer got exactly two holes-in-one during a single game is 8.57%.

C) The probability the golfer got six holes-in-one during a single game is close to 0%.

How to determine probabilities

Since a miniature golf player sinks a hole-in-one about 12% of the time on any given hole and is going to play 8 games at 18 holes each, to determine A) what is the probability the golfer got zero or one hole -in-one during a single game, B) what is the probability the golfer got exactly two holes-in-one during a single game, and C) what is the probability the golfer got six holes-in-one during a single game , the following calculations must be performed:

• 1 - 0.12 = 0.88
  
• 0.88 ^ 17 = 0.1138
  
• 0.88 ^ 18 = 0.1001
  

Therefore, the probability the golfer got zero or one hole-in-one during a single game is between 10.01% and 11.38%.

• 0.88 ^ 18 - 0.12 ^ 2 = X
  
• 0.0857 = X
  

Therefore, the probability the golfer got exactly two holes-in-one during a single game is 8.57%.

• 0.12 ^ 6 x 0.88 ^ 12 = X
  
• 0.0000000001 = X
  

Therefore, the probability the golfer got six holes-in-one during a single game is close to 0%.

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