Question

Find the force in free space between two like point charges of one coulomb each placed one metre apart

Answer 1

Explanation:

${ \rm{force = \frac{q _{1}q _{2} }{4\pi \phi \: {r}^{2} } }}$

• q is charge
• 4πQ is 1 / (9 × 10^9)
• r is separation distance

${ \rm{force = \frac{1 \times 1 \times 9 \times {10}^{9} }{ {1}^{2} } }} \\ \\ { \boxed{ \rm{force = 9 \times {10}^{9} \: newtons }}}$