Respuesta :

Given addition:

(I). → {4(2/3)} + {1(1/6)}

= {(12+2)/3}+{(6+1)/6}

= (14/3)+(7/6)

Take the LCM of 3 & 6 is 6.

= {(14×2 + 7×1)/6}

= {(28+7)/6}

= 35/6

= {5(5/6)}.

(ii).→ {5(3/5)} + (3/10)

= {(25+3)/5} + (3/10)

= (28/5) + (3/10)

Take the LCM of 5 & 10 is 10.

= {(28×2 + 3×1)/10}

= {(56 + 3)/10}

= (59/10)

= {5(9/10)}.

(iii).→ {3(5/8)} + {1(5/12)}

= {(24+5)/8} + {(12+5)/12}

= (29/8) + (17/12)

Take the LCM of 8 & 12 is 24.

= {(29×3 + 17×2)/24}

= {(87 + 34)/24}

= 121/24

= {10(1/12)}.

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Sum of fractions

Given the following sum of mixed fractions, we are to find the resulting value:

1) [tex]4\frac{2}{3} + 1\frac{1}{6} [/tex]

Convert to improper fractions

[tex]=\frac{14}{3}+\frac{7}{6} \\ =\frac{28+7}{6} \\ =\frac{35}{6}\\ =5 \frac{5}{6} [/tex]

2)Given the sum of fractions [tex]5\frac{3}{5} +\frac{3}{10}\\ [/tex]

[tex]=\frac{28}{5}+\frac{3}{10} \\ =\frac{56+3}{10} \\ =\frac{59}{10}\\ =5 \frac{9}{10} [/tex]

3) Given the sum of fractions

[tex]=8\frac{5}{8} +1\frac{5}{12} \\ ==\frac{69}{8}+\frac{17}{12} \\ =\frac{207+34}{24} \\ =\frac{241}{24}\\ =10 \frac{1}{24}[/tex]

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