Answer:
D. (14x-4)/(8x^2) and (x^2-x)/(8x^2)
Step-by-step explanation:
The least common denominator will be 8x^2, the product of 2 and x to the highest of their powers in either of the denominators.
[tex]\left\{\dfrac{7x-2}{4x^2},\ \dfrac{x-1}{8x}\right\}=\left\{\dfrac{7x-2}{4x^2}\cdot\dfrac{2}{2},\ \dfrac{x-1}{8x}\cdot\dfrac{x}{x}\right\}\\\\=\left\{\dfrac{14x-4}{8x^2},\ \dfrac{x^2-x}{8x^2}\right\}[/tex]
