The speed of the stream's current is 3.6 m/s.
The given parameters:
The change in the time of motion of the barrel is calculated as follows;
Δt = t₂ - t₁
Δt = 2:43 - 2:15
Δt = 2 min 43 s - 2 min 15 s
Δt = 43 s - 15 s
Δt = 28 s
The speed of the stream's current is calculated as follows;
[tex]v = \frac{d}{t} \\\\v = \frac{100 \ m}{28 \ s}\\\\v = 3.57 \ m/s\\\\v \approx 3.6 \ m/s[/tex]
Thus, the speed of the stream's current is 3.6 m/s.
Learn more about speed here: https://brainly.com/question/6504879