Respuesta :

Answer:

your right!!

Step-by-step explanation:

[tex] \sqrt{12} ( \sqrt{3} - x) = 15 \\ = > \sqrt{36} - \sqrt{12} x = 15 \\ = > 6 - \sqrt{12} x = 15 \\ = > - \sqrt{12} x = 15 - 6 \\ = > - \sqrt{12} x = 9 \\ = > x = \frac{9}{ - \sqrt{12} } \\ = > x = \frac{9}{ - 2 \sqrt{3} } \\ = > x = \frac{ { - \sqrt{3} }^{4} }{ 2 \sqrt{3} } \\ = > x = \frac{ - { \sqrt{3} }^{3} }{2} \\ = > x = \frac{ - 3 \sqrt{3} }{2} [/tex]

Hope you could understand.

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