what is the answer and how do i do it

Answer: Choice C
[tex]3x\sqrt{x}[/tex]
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Work Shown:
[tex]\left(9x^3\right)^{1/2}\\\\\sqrt{9x^{2+1}}\\\\\sqrt{9x^2*x^1}\\\\\sqrt{9x^2}*\sqrt{x^1}\\\\\sqrt{(3x)^2}*\sqrt{x}\\\\3x\sqrt{x}\\\\[/tex]
Answer:
[tex]3x\sqrt{x}[/tex]
Step-by-step explanation:
Quick note:
An exponent of [tex]\frac12[/tex] = [tex]\sqrt{}[/tex]
So, now we can just find the square root of 9x³
[tex]\sqrt{9x^3} = \\\\\\\sqrt9 * \sqrt{x^3}=\\\\\\3*\sqrt{x} * \sqrt{x} * \sqrt {x}=\\\\\\3x\sqrt{x}[/tex]
-Chetan K