Respuesta :

Answer: Choice C

[tex]3x\sqrt{x}[/tex]

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Work Shown:

[tex]\left(9x^3\right)^{1/2}\\\\\sqrt{9x^{2+1}}\\\\\sqrt{9x^2*x^1}\\\\\sqrt{9x^2}*\sqrt{x^1}\\\\\sqrt{(3x)^2}*\sqrt{x}\\\\3x\sqrt{x}\\\\[/tex]

Answer:

[tex]3x\sqrt{x}[/tex]

Step-by-step explanation:

Quick note:

An exponent of  [tex]\frac12[/tex] = [tex]\sqrt{}[/tex]

So, now we can just find the square root of 9x³

[tex]\sqrt{9x^3} = \\\\\\\sqrt9 * \sqrt{x^3}=\\\\\\3*\sqrt{x} * \sqrt{x} * \sqrt {x}=\\\\\\3x\sqrt{x}[/tex]

-Chetan K

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