#4: Determine the molecular formula of o compound that is made up of 61.2 g carbon, 10.4 g hydrogen and 27.6 g oxygen if its molar mass is 116.0 g/mole.

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Answer:

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[tex]\boxed{\begin{array}{c|c|c|c}\boxed{\bf Element}&\boxed{\bf No\:of\:moles}&\boxed{\bf Sample\:ratio}&\boxed{\bf Simplest\:ratio}\\ \sf C&\sf \dfrac{61.2}{12}=5.1&\sf \dfrac{5.1}{1.7}=3.0 &\sf 3 \\ \sf H&\sf \dfrac{10.4}{1}=10.4&\sf \dfrac{10.4}{1.7}=6.1 &\sf 6\\ \sf O&\sf \dfrac{27.6}{16}=1.7&\sf\dfrac{1.7}{1.7}=1&\sf 1\end{array}}[/tex]

Empirical formula:-

  • C3H6O
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