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Identify the first five terms of the sequence in which a1 = 1 and an = 3an −1 + 2 for n ≥ 2.

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Answer:

AIRTHMETIC PROGRESSION:

The number of sequence

a

,

a

+

d

,

a

+

2

d

,

a

+

3

d

,

.

.

.

.

.

is known as arithmetic sequence. In this sequence d is the difference between each consecutive term that is constant.

The formula for the nth term of an arithmetic sequence is,

T

n

=

a

+

(

n

1

)

d

The formula for the sum of first n terms of the sequence is,

S

n

=

n

2

[

2

a

+

(

n

1

)

d

]

Answer and Explanation:

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Given data:

{eq}\begin{align*} {a_1} = 1,{a_2} = 2,{b_1} = 0,{b_2} = 1\\ n \ge 3\,;\,{a_n} &= 2{a_{n - 1}} + {b_{n - 1}}\\ n \ge 2\,;\,{b_n} &=...

Answer:

1, 5, 17, 53, 161

Step-by-step explanation:

Using the recursive rule and a₁ = 1 , then

a₂ = 3a₁ + 2 = 3(1) + 2 = 3 + 2 = 5

a₃ = 3a₂ + 2 = 3(5) + 2 = 15 + 2 = 17

a₄ = 3a₃ + 2 = 3(17) + 2 = 51 + 2 = 53

a₅ = 3a₄ + 2 = 3(53) + 2 = 159 + 2 = 161

The first 5 terms are 1, 5, 17, 53, 161

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