Answer:
(2x + 1) (x - 3)
Step-by-step explanation:
A quadratic equation has the formula: ax² + bx + c. In this question:
a = 2
b = -5
c = -3
Since a is not equal to 1, we cannot simply take -3 as the product and -5 as the sum. So in order to find the factors we first multiply the value of a with the value of c, in which we get our product.
2x² - 5x - 3
Product= 2 × -3 = -6 [1 × -6 = -6]
Sum (value of b)= -5 [1 + (-6) = -5]
So the integers, when multiplied, equal to -6 and when added, equal to -5 are 1 and -6. We can now form the equation:
2x² - 6x + 1x -3
Now factorise the equation.
2x (x - 3) + 1 (x - 3)
You can see that the terms inside both the brackets [in bold] are the same; this means that your working is correct. Since both are x-3, we take that as only one x-3, in the simpler words, the answer is:
(2x + 1) (x - 3)
Take the terms in the bracket as one of the factors, and take the terms outside the bracket together as the other factor.
