Question

If the height of a right circular cone of volume 96 pie cm sq is 18cm, then what is the radius of the base of the right circular cone?

OPTIONS-
A) 4cm
B) 6cm
C) 8cm
D) 9cm

Answer 1

Via equation:
96pi=1/3 pi * r^2 * 18
16/3 pi=1/3 pi r^2
16 pi = pi r^2
16 = r^2
r = 4

Answer 2

The radius of the base of this right circular cone is equal to: A) 4cm

Given the following data:

• Volume of right circular cone = $96\pi \;cm^2$

• Height of right circular cone = 18 cm

To determine the radius of the base of the right circular cone:

Mathematically, the volume of a right circular cone is given this formula:

$V = \pi r^2\frac{h}{3}$

Where:

• V is the volume of a cone.

• r is the radius of a cone.

• h is the height of a cone.

Making r the subject of formula, we have:

$r = \sqrt{\frac{3V}{\pi h} }$

Substituting the given parameters into the formula, we have;

$r = \sqrt{\frac{3 \times 96\pi}{\pi \times 18} }\\\\r = \sqrt{\frac{3 \times 96}{ 18} }\\\\r=\sqrt{16}$

Radius, r = 4 centimeters

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