Answer:
Question:
The figure shows an arrangement of four charged particles, with angle
θ
=
30.0
∘
and distance
d
=
2.00
cm
. Particle 2 has charge
q
2
=
9.60
×
10
−
19
C
; particles 3 and 4 have charges
q
3
=
q
4
=
−
1.60
×
10
−
19
C
.
(A) What is the distance
D
between the origin and particle 2 if the net electrostatic force on particle 1 due to the other particles is zero?
(B) If particles 3 and 4 were moved closer to the
x
-axis but maintained their symmetry about that axis, would the required value of
D
be greater than, less than, or the same as in part (A)?
Electric Force:
The electric force is the force on a charged particle when it is placed near another charged body. The electric force between two charged bodies is explained by Coulomb's force. According to Coulomb's force, the electric force between two charged bodies can be mathematically expressed as follows:
F
=
k
⋅
q
1
⋅
q
2
r
2
Where:
k
is the coulomb's force.
q
1
and
q
2
are the magnitude of the charges on the charged bodies.
r
is the distance between the centers of the charged bodies.
