Respuesta :

[tex]\frac{4x}{x-1} . \frac{x^{2} -1}{3x+3} =\frac{4x}{x-1} . \frac{(x-1)(x+1)}{3(x+1)} = \frac{4x(x-1)(x+1)}{3(x-1)(x+1)} =\frac{4x}{3}[/tex]

ok done. Thank to me :>

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