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The relationship between initial work done on a cart and the velocity of the cart is [tex]W= \frac{1}{2} m(v_f^2 -v_0^2)[/tex].

What is work-energy theorem?

  • According to work-energy theorem, the work done on an object is equal to the change in mechanical energy of the object.

The relationship between initial work done on a cart and the velocity of the cart is determined by applying work-energy theorem as follows;

[tex]W = \Delta K.E\\\\W = \frac{1}{2}mv_f^2 - \frac{1}{2}mv_0^2\\\\ W= \frac{1}{2} m(v_f^2 -v_0^2)[/tex]

where;

  • [tex]v_f[/tex] is the final velocity of the cart
  • [tex]v_0[/tex] is the initial velocity of the cart

Thus, the relationship between initial work done on a cart and the velocity of the cart is [tex]W= \frac{1}{2} m(v_f^2 -v_0^2)[/tex].

Learn more about work-energy theorem here: https://brainly.com/question/22236101

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