Question

What is the answer pls for k

Answer 1

• BK||SP

Hence,

Distance of B and P on x axis= Distance of K and S on y axis

$\\ \sf{:}\longrightarrow 8-5=3$

.Hence.

K(0,-12+2)=K(0,-9)

Answer 2

coordinate of K is (0,7.5) or (0,$\frac{15}{2}$}

and

scale factor=$\frac{5}{8}$

Answer:

solution given:

O(0,0)

B(5,0)

P(8,0)

K(0,x)

S(0,-12)

and

ΔBOK $\sim$ ΔPOS

Now

By using the distance formula

d=$\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

OB=$\sqrt{(5-0)^2-(0-0)^2} =5$

OP=$\sqrt{(8-0)^2-(0-0)^2} =8$

OK=$\sqrt{(0-0)^2-(x-o)^2} =x$

OS=$\sqrt{(0-0)^2-(-12-0)^2} =12$

since

ΔBOK is similar to ΔPOS

So their side will be proportional.

$\frac{OK}{OS}=\frac{OB}{OP}$

taking two proportional only

$\frac{x}{12} =\frac{5}{8}$

$x=\frac{ 12*5}{8}=\frac{15}{2}$=7.5

Now

coordinate of K is (0,7.5) or (0,$\frac{15}{2}$}

and

Scale factor = Dimensions of the new shape ÷ Dimensions of the original shape.

scale factor=$\frac{OB}{OP}=\frac{5}{8}$