Question

Tanias little sister sits 1.2m from the pivot of a see-saw. Her mass provides a force of 200 N. Tania pushes down on the other end of the see-saw to make it balance. The maximum pushing force she can provide is 100 N. How far from the pivot must tania push to make the see-saw balance?​

Answer 1

The distance at which Tania must push to make the see-saw balance is 2.4 m.

For the see-saw to balance, the moment due to Tania's little sister's weight,M must balance the moment due to Tania's push, M'.

Moment of a Force

The moment of a force, M is the product of the force, F and its perpendicular distance from the point of action, d.

Thus M = Fd

Let

• W = Tania's little sister weight = 200 N,
• d = distance of Tania's little sister from pivot = 1.2 m,
• F = Tania's push force = 100 N and
• L = distance of Tania's force from pivot.

Since both moments are equal for the see-saw to balance,

M = M'

Wd = FL

So, making L subject of the formula, we have

L = Wd/F

Substituting the values of the variables into the equation, we have

L = 200 N × 1.2 m/100 N

L = 2 × 1.2 m

L = 2.4 m

So, the distance at which Tania must push to make the see-saw balance is 2.4 m.

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