Hi there!
We can use the kinematic equation:
[tex]v_f = v_i + at[/tex]
vf = final velocity (0 m/s, breaking to a stop)
vi = initial velocity (28 m/s)
a = acceleration (-6.4 m/s², breaking)
time (sec)
Plug in the given values and solve.
[tex]0 = 28 - 6.4t\\\\-28 = 6.4t\\\\\large\boxed{t = 4.375 s}[/tex]