Find the equation of the line that passes through points A and B

Answer:
y= 2x-1
Step-by-step explanation:
We know two points on the line, so we can find the slope
(2,3) and (4,7)
The slope is found by using the slope formula
m = ( y2-y1)/(x2-x1)
m = ( 7-3)/(4-2) = 4/2 = 2
We can use the slope intercept form of the equation
y = mx+b where m is the slope and b is the y intercept
y = 2x+b
Using one of the points to substitute into the equation we can find b
3 = 2(2)+b
3 = 4+b
-1 =b
y= 2x-1
Answer:
y = 2x - 1
Step-by-step explanation:
The equation of a line in slope- intercept form is
y = mx + c ( m is the slope and c the y- intercept )
Calculate m using the slope formula
m = [tex]\frac{y_{2}-y_{1} }{x_{2}-x_{1} }[/tex]
with (x₁, y₁ ) = A (4, 7 ) and (x₂, y₂ ) = B (2, 3 )
m = [tex]\frac{3-7}{2-4}[/tex] = [tex]\frac{-4}{-2}[/tex] = 2 , then
y = 2x + c ← is the partial equation
To find c substitute either of the 2 points into the partial equation
Using (2, 3 )
3 = 4 + c ⇒ c = 3 - 4 = - 1
y = 2x - 1 ← equation of line